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Screen Recording 2024-03-03 at 12.03.07 AM

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Screen Recording 2024-03-03 at 12.03.07 AM

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1st way: exp ∫(e^x)/x (1+x log(x)) dx

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1st way: exp ∫(e^x)/x (1+x log(x)) dx

10 Views

AI 2008 Hindustan: Evaluate integral ∫ 2/3 cos(x)/sin^2(x) dx

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AI 2008 Hindustan: Evaluate integral ∫ 2/3 cos(x)/sin^2(x) dx

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MPPET 1996 Hindustan: trig integral ∫ sin^2(x) -cos^2(x)/(sin^2(x) cos^2(x)) dx

2:09

MPPET 1996 Hindustan: trig integral ∫ sin^2(x) -cos^2(x)/(sin^2(x) cos^2(x)) dx

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MP 8,93,96,97,99 Hindustan: Evaluate ∫ sec(x)/(sec(x)-tan(x)) dx

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MP 8,93,96,97,99 Hindustan: Evaluate ∫ sec(x)/(sec(x)-tan(x)) dx

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CBSE 2000 Hindustan: integral (1+tan(x))/(x+log(sec(x)) dx

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CBSE 2000 Hindustan: integral (1+tan(x))/(x+log(sec(x)) dx

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MP 2000 Hindustan: Evaluate ∫(tan(x)+cot(x))^2 dx

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MP 2000 Hindustan: Evaluate ∫(tan(x)+cot(x))^2 dx

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2nd way: integral ∫ log √x(x^n) dx

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2nd way: integral ∫ log √x(x^n) dx

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wala lang 😂

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1st/2 parts stat: SLR ∑ŷk = ∑yk where k=1,n

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1st/2 parts stat: SLR ∑ŷk = ∑yk where k=1,n

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If u=f(y/x) then prove that x∂u/∂x + y∂u/∂y = 0

1:55

If u=f(y/x) then prove that x∂u/∂x + y∂u/∂y = 0

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#2 2023 MIT Integration Bee Qualifying Exam

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#2 2023 MIT Integration Bee Qualifying Exam

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Hyper

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#17 2010 MIT Integration Bee Qualifying Exam

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#17 2010 MIT Integration Bee Qualifying Exam

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2nd way: integral ∫1/√(arc sin(a)x - √√b) dx Calculus

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2nd way: integral ∫1/√(arc sin(a)x - √√b) dx Calculus

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1st/2ways: Find trig integral ∫sec^2(x)/csc^2(x) dx

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1st/2ways: Find trig integral ∫sec^2(x)/csc^2(x) dx

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bj HARU dance

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xinniandiyiyu__01

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2nd/2 ways: #1 2019 MIT Integration Bee Final

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2nd/2 ways: #1 2019 MIT Integration Bee Final

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2nd part: n^2 = (tn - tn-1)^2 where tn = nth triangular number

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2nd part: n^2 = (tn - tn-1)^2 where tn = nth triangular number

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2 ways: Find ∫(ax^x+bx+c) dx

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2 ways: Find ∫(ax^x+bx+c) dx

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