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Bijection of elements in tn & a pair of elements of (n+1)
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integral ∫ x dx withOUT using Power rule.
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Why the mean of AP is the median of AP? mean=median?
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2010 #2 MIT Integration Bee
Fill in each blank using either mean or median.
What does SS tell us about a set of data? Under what circumstances will the value of SS equal 0?
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2nd way: integral ∫x^k ln(x) dx = x^(k+1)/(k+1) ln(x) - x^(k+1)/(k+1)^2 + C where C ≠ -1
integral ∫x^3/(x+2) dx
Consider the mode, median, mean.