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1st/2ways: Taylor series of sin(x)
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MP 2000 Hindustan: Evaluate ∫(tan(x)+cot(x))^2 dx
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MP 98 Hindustan: Evaluate (i) ∫e^loge(x) dx (ii) ∫e^(-loge(x)) dx
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2nd way: integral ∫ log √x(x^n) dx
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AI 2008 Hindustan: Evaluate integral ∫ 2/3 cos(x)/sin^2(x) dx
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RPET 2003 Hindustan: integral ∫sin^4(x)-cos^4(x) dx
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2nd/2ways: Taylor series of cos(x)
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derivative: If x=cos(log(y)), show that (1-x^2)y2 - xy1 = y
2nd/2 ways: exp log integral ∫e^(n ln(x)) dx
2nd way: ∫(x+3)/(x^2+6x)^2 dx vs ∫(x+3)(x^2+6x)^2 dx
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2nd way: integral ∫x^2 √(x^3+1) dx vs ∫x^3 √(x^3+1) dx
2nd/2ways: Taylor series of sin(x)
2nd way: exp integral ∫e^(a√x)/√x dx
Alternate way: derivative If y=e^(a arc sin(x)), prove that (1-x^2)y2-xy1=a^2y
2nd way: log ∫1/(x(10+7log(x) + (log(x))^2) dx
2nd way: trig integral ∫(sin^6(x)+cos^6(x))/(sin^2(x) cos^2(x)) dx
Utagoe wa Mille-Feuille [Harmony of Mille-Feuille] Episódio 9 - SUB PTBR
2nd way: integral ∫1/(√(px-q) - √(px+r)) dx
Do you remember the episode in Boonie Bears where King Jiji looks for the treasure?
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Screen Recording 2023-12-06 at 3.07.30 AM