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4 ways: Evaluate Σ(2k+1) k=1,20

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1st/2 ways: Show 1+3+5+ ... +(2n-1) + (2n+1) + (2n-1)+...+5+3+1= n^2 + (n+1)^2
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1st/2 ways: Show 1+3+5+ ... +(2n-1) + (2n+1) + (2n-1)+...+5+3+1= n^2 + (n+1)^2

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trig Show (sec(x)+1)/sec^2(x) = sin^2(x)/(sec(x)-1)

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Simplify the Boolean function F=A+A'B

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The number of solutions of the equation x^(log10(x)) = 100x

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2nd way: Evaluate ∫ 1/√(1-e^(2x)) dx

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